Question

Using 0.082 as your R value, what is the pressure in atm, of 0.25 mols of a gas at 300K in a 4L container?

Answer 1

`\text{ }1.5375\text{ atm}`

Step-by-step explanation:

Here, we want to get the value of the pressure in atm

Mathematically, we can use the ideal gas equation for this

This is calculated as follows:

`\begin{gathered} PV\text{ =nRT} \\ P\text{ = }(nRT)/(V) \end{gathered}`

where n is the number of moles which is given as 0.25

R is the molar gas constant which is 0.082

T is the temperature, given as 300K

V is the volume, given as 4L

Substituting these values, we have it that:

`P=(0.25*0.082*300)/(4)\text{ = }1.5375\text{ atm}`