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If sin x = .42, what is cos x?

User Nehz
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We\ know:\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\to\cos x=√(1-\sin^2x)\\\\\sin x=0.42\\subtitute\\\\\cos x=√(1-0.42^2)=√(1-0.1764)=√(0.8236)\approx0.91
User Keltex
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