Question

Divide the combinations.

60C3 / 15C3

Answer 1

I hope you know what '!' means
2!=2
3!=6
4!=24
basicalkly times every natural number including and before that number


nCr=
`(n!)/(r!(n-r)!)`
so

`(60C3)/(15C3)`=

`( (60!)/(3!(60-3)!) )/( (15!)/(3!(15-3)!) )`=

`( (60!)/(3!(60-3)!))((3!(15-3)!)/(15!))`=

`( (60!)/(3!(57)!))((3!(12)!)/(15!))`=

`((60!)(3!)(12!))/((3!)(57!)(15!))`=

`((60!)(12!))/((57!)(15!))`=

`((60!))/((57!)(15)(14)(13))`=

`((60)(59)(58))/((15)(14)(13))`=

`((30)(59)(58))/((15)(7)(13))`=

`((6)(59)(58))/((3)(7)(13))`=

`(6844)/(91)`