We balance the enthalpy absorbed by the steel and the enthalpy lost by wood. In this case, we use mCp ΔT to describe the problem. Cp (W) is 4 Cp(S). assuming the same mass,
mCp(W) ΔT1 = mCp(S) ΔT2
4* ΔT1 = 40
ΔT1 = 10. Hence the temperature of the wood is decreased by 10 degrees