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Derivative of (4e)^x

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we are given the expression (4e) ^x and is asked to derive the expression. we distribute first the equations resulting to 4^x e^x = y. using the rule of products,
y = 4^x e^xy' = 4^x ln 4 e^x + 4^x e^x
The final answer is y' = 4^x ln 4 e^x + 4^x e^x
User Bajrang Hudda
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