Given the following polynomial find the maximum possible number of turning points. f(x)=x^11+x^10+x^12+x^9

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asked Oct 25, 2017 12.6k views

1 Answer

Stephen Hosking · Answer 1 · 2017-10-29T12:52:41+0000

turning points are inflection points

think
1st degree (linear) has no turning/inflecion points
2nd degree (quadratic, parabola) has 1 turning/inflection point
so
nth degree has n-1 turning/inflection point

this is 11th degree since highest power is 12
12-1=11
11 turning oints

Given the following polynomial find the maximum possible number of turning points. f(x)=x^11+x^10+x^12+x^9

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