Question

Someone please help me :'(

On a particular day, the wind added 2 miles per hour to Alfonso's rate when he was cycling with the wind and subtracted 2 miles per hour from his rate on his return trip. Alfonso found that in the same amount of time he could cycle 60 miles with the wind, he could go only 48 miles against the wind.What is his normal bicycling speed with no wind?

Answer 1

Hello,

Let's assume v=the normal bicycling speed with no wind
and t the same amount of time...

60=(v+2)*t (1)
48=(v-2)*t (2)

(1)/(2)==>60/48=(v+2)/(v-2)

==>5(v-2)=4(v+2)
==>5v-4v=8+10
==>v=18 (mi/h)