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Evaluate the integral of tan^2(x)sec(x).

User Laruiss
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Final answer:

To evaluate the integral of tan^2(x)sec(x), we can use a technique called substitution. Let's substitute u = tan(x). Then, du = sec^2(x)dx. Now, the integral becomes the integral of u^2 du. Integrating this, we get ½u^3 + C, where C is the constant of integration.

Step-by-step explanation:

To evaluate the integral of tan^2(x)sec(x), we can use a technique called substitution. Let's substitute u = tan(x). Then, du = sec^2(x)dx. Now, the integral becomes the integral of u^2 du. Integrating this, we get ½u^3 + C, where C is the constant of integration.

User Arthur Skirvin
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Based in your question that ask to evaluate the integral of tan^2(x)sec(x), base on my calculation and the use of the integral procedures and formula i came up with a solution that could answer your question and the evaluated answer is tan(x)sec(x)−∫(sec2(x)−1)sec(x)dx
User Jaber
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