Question

A jet plane comes in for a downward dive as shown in the figure below.

The bottom part of the path is a quarter circle having a radius of curvature of 350m . According to medical tests, pilots lose consciousness at an acceleration of 5.50g. At what speed (in m/s) will the pilot black out for this dive?

Answer 1

As we know that centripetal acceleration during circular motion is given by the formula

`a = (v^2)/(R)`

as we know that maximum value of acceleration is given as

`a = 5.50 g`

here we know that

`g = 9.81 m/s^2`

so here we will have

`a = 5.50 (9.81 m/s^2)`

`a = 54 m/s^2`

now we will have from above first equation

`54 = (v^2)/(R)`

`54 = (v^2)/(350)`

`v = 137.4 m/s`

so maximum possible speed will be 137.4 m/s