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A jet plane comes in for a downward dive as shown in the figure below.

The bottom part of the path is a quarter circle having a radius of curvature of 350m . According to medical tests, pilots lose consciousness at an acceleration of 5.50g. At what speed (in m/s) will the pilot black out for this dive?

1 Answer

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As we know that centripetal acceleration during circular motion is given by the formula


a = (v^2)/(R)

as we know that maximum value of acceleration is given as


a = 5.50 g

here we know that


g = 9.81 m/s^2

so here we will have


a = 5.50 (9.81 m/s^2)


a = 54 m/s^2

now we will have from above first equation


54 = (v^2)/(R)


54 = (v^2)/(350)


v = 137.4 m/s

so maximum possible speed will be 137.4 m/s

User Mike Spear
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