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What mass of copper is produced when 3.8 G of iron reacts with the excess copper (H) sulfate according to the Equation?Fe + CuSO4 ----> FeSO4 + Cu

What mass of copper is produced when 3.8 G of iron reacts with the excess copper (H-example-1
User Yorgos
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2 Answers

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When 3.8 grams of iron reacts with excess copper sulfate, approximately 4.32 grams of copper are produced.

The correct answer is option D.

When 3.8 grams of iron reacts with excess copper(II) sulfate (CuSO4), the following chemical reaction occurs:

Fe + CuSO4 → FeSO4 + Cu

According to the balanced equation, one mole of iron (Fe) reacts with one mole of copper(II) sulfate (CuSO4) to produce one mole of copper (Cu). Therefore, to calculate the mass of copper produced, we need to determine the moles of iron and use the molar masses of iron and copper.

1. Moles of Iron:

Molar mass of iron (Fe) = 55.845 g/mol

Mass of iron = 3.8 g

Moles of iron = mass / molar mass = 3.8 g / 55.845 g/mol ≈ 0.068 moles

2. Moles of Copper Produced:

From the balanced equation, we know that the mole ratio of iron to copper is 1:1. Therefore, the moles of copper produced are equal to the moles of iron reacted.

Moles of copper produced = 0.068 moles

3. Mass of Copper Produced:

Molar mass of copper (Cu) = 63.546 g/mol

Mass of copper produced = moles x molar mass = 0.068 moles x 63.546 g/mol ≈ 4.32 g

User Mshameer
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Fe + CuSO₄ ----> FeSO₄ + Cu

According to that equation, 1 mol of Fe will react with 1 mol of CuSO₄ to give 1 mol of FeSO₄ and 1 mol of Cu.

The first step to solve the problem is to find the number of moles of Fe that we have in 3.8 g of it. To do that we have to use the molar mass.

molar mass of Fe = 55.85 g/mol

number of moles of Fe = mass of Fe/molar mass of Fe

number of moles of Fe = 3.8 g /(55.85 g/mol)

number of moles of Fe = 0.068 moles of Fe

Once that we know that 3.8 grams of Fe represents 0.068 moles of Fe, we can find the number of moles of Cu produced by those moles (since Fe reacts with excess of CuSO₄). According to the coefficients of the equation of the reaction:

number of moles of Cu produced = 0.068 moles of Fe * 1 mol of Cu/(1 mol of Fe)

number of moles of Cu produced = 0.068 moles of Cu

Finally we can convert those moles of Cu produced into grams using the molar mass of Cu.

molar mass of Cu = 63.55 g/mol

mass of Cu produced = 0.068 moles * 63.55 g/mol

mass of Cu produced = 4.32 g

Answer: b) 4.3 g of Cu are produced.

User MJK
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