Question

A geometric sequence is defined by the explicit formula an=5(-4)^n-1 what is the recursive formula for the nth term of this sequence?

Answer 1

Hello,


`a_(n)=5*(-4)^(n-1)\\ a_(n-1)=5*(-4)^(n-2)\\\\ (a_(n))/(a_(n-1))=(-4)^(n-1-(n-2))=-4\\\\ Formula\ is\ :\\ a_(n)=-4*a_(n-1)\\ a_(1)=5\\`