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Express the given quantity as a single logarithm: 1/5 ln(x + 2)^5 + 1/2 [ln x − ln(x^2 + 3x + 2)^2]
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Express the given quantity as a single logarithm: 1/5 ln(x + 2)^5 + 1/2 [ln x − ln(x^2 + 3x + 2)^2]
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Aug 24, 2017
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Express the given quantity as a single logarithm:
1/5 ln(x + 2)^5 + 1/2 [ln x − ln(x^2 + 3x + 2)^2]
Mathematics
high-school
Edepperson
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Hello,
1) Conditions:
x+2>=0==>x>-2
x>=0
So x>=0
1/5 ln(x+2)^5 +1/2 [ln x -ln(x^2+3x+2)^2]
=ln(x+2)+ ln√x - ln(x+1)(x+2)
Meadowstream
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Aug 25, 2017
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Based on your question where to have the quantity to be express as a single logarithm, the given algorithm in your question must first to be analyze and based on my calculation and my simplyfication the answer is ln is equals to the quotients of sqrt of x over x plus 1.
Fariha
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Aug 27, 2017
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Fariha
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