Question

A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t² + 60t + 6. What will the height be at t = 3 seconds?

A.) 35 feet
B.) 40 feet
C.) 42 feet
D.) 45 feet

Answer 1

The height of the ball when it hits t = 3 seconds will be 42 feet.

Step-by-step explanation:

The user above me provides a very helpful explanation, so I am only writing this in his/her/their honor for his/her/their work :D

h = -16t² + 60t + 6

h = (-16)(3 s)² + (60)(3) + 6 = 42

Answer 2

To answer the question, directly substitute the value given for t to the given function of height.
h = -16t² + 60t + 6
h = (-16)(3 s)² + (60)(3) + 6 = 42
Therefore, the height of the ball after 3 seconds is 42 ft.