Question

How many moles of sodium chloride (NaCl) solute are in 205 grams of a 92.5 percent by mass solution?

A.) 1.92 mol NaCl
B.) 2.63 mol NaCl
C.) 3.24 mol NaCl
D.) 7.71 mol NaCl

Answer 1

Answer: The correct answer is option (C).

Step-by-step explanation:

Mass of the solution = 205 g

Mass by mass percentage of the solution = 92.5 %

`m/m\%=\frac{\text{Mass of the Sodium Chloride}}{\text{Mass of the solution}}* 100`

`92.5\%=\frac{\text{Mass of the sodium chloride}}{205 g}* 100`

Mass of the sodium chloride :

`=92.5* (205 g)/(100)=189.625 g`

Moles of the Sodium chloride:

`\frac{\text{Mass of the sodium chloride}}{\text{Molar mass of the sodiu chloride}}=(189.625 g)/(58.44 g/mol)=3.24 mol`

Hence,the correct answer is option (C).

Answer 2

Base in your question, the possible answer to your question and the possible answer among the choices that what could be the mole of sodium chloride solute are in 205g of 92.5 percent mass solution and the answer is C. 3.24 mol NaCl