Answer:
CrSO₃
Step-by-step explanation:
Given parameters:
Mass of sample = 3.78g
Mass of chromium = 1.52g
Mass of sulfur = 0.88g
Mass of oxygen = 1.38g
Unknown:
Empirical formula of the compound = ?
Solution:
The empirical formula of a compound is the simplest formula of such a compound.
To solve this problem, follow the chart below:
Elements Cr S O
Mass 1.52 0.88 1.38
Molar mass 52 32 16
Number of moles 1.52/52 0.88/32 1.38/16
0.029 0.028 0.086
Divide through by
the smallest 0.029/0.028 0.028/0.028 0.086/0.028
1 1 3
So,
The empirical formula is CrSO₃