Question

Calculate the energy released when a 28.9 gram piece of paper is cooled from its melting point of 1083 degrees Celsius to 25.0 degrees Celsius. The specific heat of copper is .385 j/g Celsius.

Answer 1

use equation: ΔH = MCΔT

M = mass of copper
C = specific heat capacity of copper
ΔT = temp. change

ΔH = 28.9 x 385 x 3.9 =43393.35J or 43.39KJ

Answer 2

Answer : The energy released will be, -11771.837 J

Solution :

Formula used :

`Q=m* c* \Delta T=m* c* (T_(final)-T_(initial))`

where,

Q = heat released = ?

m = mass of copper = 28.9 g

c = specific heat of copper =
`0.385J/g^oC`

`\Delta T=\text{Change in temperature}`

`T_(final)` = final temperature =
`25^oC`

`T_(initial)` = initial temperature =
`1083^oC`

Now put all the given values in the above formula, we get :

`Q=28.9g* 0.385J/g^oC* (25-1083)^oC`

`Q=-11771.837J`

Therefore, the energy released will be, -11771.837 J