Question

Find the values of the six trigonometric functions of theta based on the following constraints:

1.) Theta is found in quadrant II.
2.) sin theta = 3/5

Answer 1

Hello,

1)
sin x=3/5==>x=126.869897...° (since in quadrant II)

2)==>cos x<0
cos x=-√(1-sin ² x)=-√(1-9/25)=-4/5

tan x=(3/5)/(-4/5)=-3/4

cotg x=-4/3 =1/tan x

sec x=1/cos x=-5/4

cosec x=1/sin x=5/3

Answer 2

The first step to take here is to evaluate the equation sin theta = 3/5. Theta is equal to 36.86 degrees. Since the angle lies in the second quadrant, the angle is 180-36.86 or equal to 143.13 degrees. Thus, sin theta = 3/5cos theta = -4/5tan theta = -3/4csc theta = 5/3sec theta = -5/4cot theta = -4/3