If a 2.00 kg ball is thrown straight upward with a KE of 500J. what maximum height will it reach?

asked Jul 26, 2023 214k views

9 votes

by Blabb

7.9k points

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11 votes

Answer: 25.51m

Explanation: KEi +PEi = KEf + PEf

KEi = 500, PEi = 0, KEf = 0, PEf = 500

PE = fg * m * h

500 = 9.8 * 2 * h

h = 25.51m

Slago answered Aug 1, 2023

by Slago

7.5k points

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