Question

write the equation of the line that passes through the point (-3, -1) with a slope of -2/3. y = (-⅔)x - 8 y = (-⅔)x - 1 y = (-⅔)x - 11/3 y = (-⅔)x - 3

Answer 1

y = mx + b
slope(m) = -2/3
(-3,-1)...x = -3 and y = -1
now we sub
-1 = -2/3(-3) + b
-1 = 2 + b
-1 - 2 = b
-3 = b

so ur equation is : y = -2/3x - 3