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Calculate the volume of 1.00 x 10^-2M KOH solution containing 3.00 x 10^-1 mol of solute?

1 Answer

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Volume = ?

Molarity (M) = 1.00 x 10⁻² M

moles (n) = 3.00 x 10⁻¹ mol

V = n / M

V = 3.00 x 10⁻¹ / 1.00 x 10⁻²

V = 30 L
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