Question

Write the equation of the line that contains the points (1, -6) and (-3, 10)

Answer 1

First, let's calculate the slope:

`\begin{gathered} m=(-6-10)/(1-(-3))\rightarrow m=(-16)/(1+3)\rightarrow m=(-16)/(4) \\ \rightarrow m=-4 \end{gathered}`

Using this, point (1, -6) and the slope-point form, we get that the equation is:

`\begin{gathered} y-(-6)=-4(x-1) \\ \rightarrow y+6=-4x+4 \\ \rightarrow y=-4x-2 \end{gathered}`

Thereby, the equation of the line is

`y=-4x-2`