Question

What volume of the 5.00% (w/v) citrie acid solution described above would be needed to provide 738 mg citric acid for a reaction?

738 mg of eitrie acid for a reaction Show your work using dimensional analysis and report yo
answer with the correct number of significant figures, (You should know the relationship betw
grams and milligrams.)

Answer 1

`V=14.76mL`

Step-by-step explanation:

Hello!

In this case, since the given 5.00 % (w/v) can also be represented in terms of mass of solute over volume of solution, we need to make sure that the same system of units is used, in this case, the appropriate units for that unit of concentration should be g/mL, and therefore, we first need the mass of citric acid in grams:

`m=738mg*(1g)/(1000mg) =0.738 g`

Thus, by using the w/v percent, we obtain the following volume of solution:

`V=(m)/(m/w)*100\%`

So we plug in to obtain:

`V = (0.738g)/(5.00\%)*100\% \\\\V=14.76mL`

Best regards!