Question

Consider the function f(x) = 2sin(x2) on the interval 0 ≤ x ≤ 3.. . (a) Find the exact value in the given interval where an antiderivative, F, reaches its maximum.. x = . . . . (b) If F(1) = 9, estimate the maximum value attained by F. (Round your answer to three decimal places.). y ≈ .

Answer 1

So base in your question where there is a function f(x)=2sin(x^2) on a interval the following are the answer to your question on A and B.

A. X=pi/2 is the value of X in the given interval.
B. the possible value of x is 1 2 and 3 which gives the value of 0.034, 0.14, 0.313

i hope i answered your question