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Extra credit work I really dont know how to do this and grades not so good HELP
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43 votes
43 votes
Extra credit work I really dont know how to do this and grades not so good HELP

Extra credit work I really dont know how to do this and grades not so good HELP-example-1
User Miqe
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1 Answer

17 votes
17 votes

Step1; Draw the Diagram

From the diagram, we can see a right-angle triangle

Using Pythagoras theorem


\begin{gathered} \text{hypotenues}^2=\text{opposite}^2+\text{adjacent}^2 \\ \text{hypotenues}=22.5\operatorname{mm} \\ \text{opposite}=18\operatorname{mm} \\ \text{adjacent}=r \end{gathered}

hence we have


\begin{gathered} 22.5^2=18^2+r^2 \\ r^2=22.5^2-18^2 \\ r^2=182.25 \\ r=\sqrt[]{182.25} \\ r=13.5\operatorname{mm} \end{gathered}

Hence the radius of circle C is 13.5mm


\begin{gathered} \text{diameter}=\text{ 2}* radius \\ =2*13.5=27 \\ \text{Diameter of circle C=27mm} \end{gathered}

Therefore the diameter of the circle is 27mm

Extra credit work I really dont know how to do this and grades not so good HELP-example-1
User Mehdi Farhadi
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