Question

How many moles in 4.93 x 10E23 atoms of silver?

Answer 1

0.819 mol Ag

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

4.93 × 10²³ atoms Ag

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

1. Set up:
   `\displaystyle 4.93 \cdot 10^(23) \ atoms \ Ag((1 \ mol \ Ag)/(6.022 \cdot 10^(23) \ atoms \ Ag))`
2. Divide:
   `\displaystyle 0.818665 \ mol \ Ag`

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.818665 mol Ag ≈ 0.819 mol Ag