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sketch the graph: y = cot (pi/4 x). . well the period would be pi/b . - pi/ (pi/4 x). - I end up getting a period = 4. . HOW DO I FIND THE VERTICAL ASYMPTOTES?

User Zonble
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Answer:

Refer the attached figure.

Vertical asymptote
x=4+4n

Explanation:

Given : Function
y=\cot ((\pi)/(4)x)

To find : Sketch the given function and find the vertical asymptotes of the function ?

Solution :

Function
y=\cot ((\pi)/(4)x)

Sketch the function on the graph.

Refer the attached figure.

Now, Vertical asymptote is defined as

On a graph, a line which is approached by a curve but never reached.

i.e. on different values of x y tends to infinity.

When we see the graph the vertical asymptote of the function is given by


x=4+4n for n=0,1,2,3...

sketch the graph: y = cot (pi/4 x). . well the period would be pi/b . - pi/ (pi/4 x-example-1
User William Pownall
by
7.7k points
3 votes
The general form of the equation is acot (bx−c)+d to find the variables used to find the amplitude, period, phase shift, and vertical shift where a=1, b=π/4, c=0 and d=0
Period is pi/b or equal to 4.

The vertical asymptote is 4pi n where n is integer.
Attached is the sketch of the graph

sketch the graph: y = cot (pi/4 x). . well the period would be pi/b . - pi/ (pi/4 x-example-1
User Habba
by
8.0k points

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