Question

Can someone please answer. There is one problem. There's a picture. Thank you!

Answer 1

`(95^o)/(360^o)=(19)/(72)\\\\Perimeter\ of\ the\ circle:L=2\pi\cdot6=12\pi\approx12\cdot3.14=37.68\\\\\widehat{DG}=(19)/(72)\cdot37.68\approx9.95\\\\Answer:\boxed{9.95}`

Answer 2

Degrees:
`s = (\pi)/(180)\theta r`

`s = (\pi)/(180)((s)/(r))(r)`

`s = (\pi)/(180)((95)/(6))(6)`

`s = (\pi)/(180)(15.8\bar{3})(6)`

`s = (\pi)/(180)(95)`

`s = (95\pi)/(180)`

`s = (19\pi)/(36)`

`s = 95\°`

Radians:
`s = \theta r`

`s = (95)/(6)(6)`

`s = 95`

`s = (19\pi)/(36)`

Arc Length =
`(\theta)/(360) * C`
Arc Length =
`(95)/(360) * 2(3.14)(6)`
Arc Length =
`(19)/(72) * 2(18.84)`
Arc Length =
`(19)/(72) * 37.68`
Arc Length =
`(715.92)/(72)`
Arc Length =
`9.94\bar{3}`

The answer is A.