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Which point is on the circle described by (x - 2)2 + (y + 3)2 = 4?

A. (2, -5)
B. (2, 0)
C. (0, 0)
D. (1, -4)

User DPlusV
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2 Answers

4 votes
the answer is B last time i got this question on a test and i got it right nit sure if its the same test but it is the same question you can try ! sorry for not remembering quite well
User KRiZ
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2 votes

Answer: The correct option is (A) (2, -5).

Step-by-step explanation: We are to select the point that is on the circle described by the following equation :


(x-2)^2+(y+3)^2=4~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Option (A) :

(x, y) = (2, -5).

We have


L.H.S.\\\\=(x-2)^2+(y+3)^2\\\\=(2-2)^2+(-5+3)^2\\\\=0+4\\\\=4\\\\=R.H.S.

So, the point (2, -5) lies on the circle (i). And so, option (A) is correct.

Option (B) :

(x, y) = (2, 0).

We have


L.H.S.\\\\=(x-2)^2+(y+3)^2\\\\=(2-2)^2+(0+3)^2\\\\=0+9>4=R.H.S.

So, the point (2, 0) lies outside the circle (i). And so, option (B) is incorrect.

Option (C) :

(x, y) = (0, 0).

We have


L.H.S.\\\\=(x-2)^2+(y+3)^2\\\\=(0-2)^2+(0+3)^2\\\\=4+9=13>4=R.H.S.

So, the point (0, 0) lies outside the circle (i). And so, option (C) is incorrect.

Option (D) :

(x, y) = (1, -4).

We have


L.H.S.\\\\=(x-2)^2+(y+3)^2\\\\=(1-2)^2+(-4+3)^2\\\\=1+1<4=R.H.S.

So, the point (2, -5) lies inside the circle (i). And so, option (D) is incorrect.

Thus, (A) is the correct option.

User Felix Fung
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