Question

Simplify 48 - 3 x squared over x squared +x-20

Answer 1

`(48-3x^2)/(x^2+x-20)`
remember difference of 2 perfect squares,
a^2-b^2=(a+b)(a-b)
factor them to find ones

48-3x^2=3(16-x^2)=(3)(4+x)(4-x)

x^2+1x-20
find what 2 numbers multiply to -20 and add to 1
-4 and 5
(x-4)(x+5)

now we have

`((3)(4-x)(4+x))/((x-4)(x+5))`
we can clear that (x-4) by force undistributing a negative 1 from that (4-x)
(4-x)=(-1)(x-4)

`((3)(-1)(x-4)(4+x))/((x-4)(x+5))`=

`((3)(-1)(4+x))/((x+5))`=

`((-3)(4+x))/((x+5))`=

`((-12-3x))/((x+5))`

Answer 2

48-
`√(3x)/ √(x) +x-20`

x+28-
`√(3)` Answer