Question

A carton has a length of fraction 2 and 1 over 4 feet, width of fraction 1 and 3 over 5 feet, and height of fraction 2 and 1 over 3 feet. What is the volume of the carton?

Answer 1

if its a Rectangular Prism you should just time all of them together and that would make 8 2 over 5

Answer 2

`(42)/(5)\text{ ft}^3`.

Explanation:

We have been given that a carton has a length of fraction
`2(1)/(4)` feet, width of fraction
`1(3)/(5)` feet, and height of
`2(1)/(3)` feet. We are asked to find the volume of the carton.

The volume of carton will be product of length, width and height.

Let us convert mixed fractions into improper fractions as:

`2(1)/(4)=(9)/(4)`

`1(3)/(5)=(8)/(5)`

`2(1)/(3)=(7)/(3)`

`\text{Volume of the carton}=(9)/(4)\text{ ft}*(8)/(5)\text{ ft}*(7)/(3)\text{ ft}`

`\text{Volume of the carton}=(3)/(1)*(2)/(5)*(7)/(1)\text{ ft}^3`

`\text{Volume of the carton}=3*(2)/(5)*7\text{ ft}^3`

`\text{Volume of the carton}=(42)/(5)\text{ ft}^3`

Therefore, the volume of the carton is
`(42)/(5)\text{ ft}^3`.