Question

How many atoms are in 1.4 mol of phosphorus trifluoride (PF3)?

Answer 1

One mol is equal to the Avogadro's Number. Using this equivalence, we can obtain the number of molecules contained in 1.4 mol:


`1.4\ mol\ PF_3\cdot (6.022\cdot 10^(23)\ molec)/(1\ mol) = 8.43\cdot 10^(23)\ molec\ PF_3`

Each molecule contains 4 atoms: three atoms of fluorine and one atom of phosphorus:


`8.43\cdot 10^(23)\ molec\ PF_3\cdot (4\ atoms)/(1\ molec\ PF_3) = \bf 3.37\cdot 10^(23)\ atoms`

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