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Probability theory predicts that there is a 70% chance of a particular soccer player making two penalty shots in a row. If the soccer player taking two penalty shots is simulated 2500 times in about how many of the simulations would you expect at least one missed shot

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The probability of the player missing a shot at least once is 1.00 - 0.70 = 0.3.
Therefore the average number of missed double goals in 2500 trials is given by:

2500*0.3=750
User Guneysus
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