Question

PLEASE HELP ME!!!!!!!! 

Find the angle between the given vectors to the nearest tenth of a degree.

u = <-5, -4>, v = <-4, -3>

Answer 1

Angle θ between two vectors is given by,
`\theta =cos^(-1)( (u \cdot v)/(|u||v|) )`; where
`u \cdot v=-5(-4)+(-4)(-3)=20+12=32`;
`|u|= \sqrt{ (-5)^(2) + (-4)^(2) } = √(25+16) = √(41)` and
`|v|=\sqrt{ (-4)^(2) + (-3)^(2) } = √(16+9) = √(25)=5`.
Therefore,
`\theta =cos^(-1)( (32)/( 5√(41)) )=cos^(-1)0.9995=1.8^o`