Question

How many moles in 2.21 x10E24 atoms of aluminum

Answer 1

3.67 mol Al

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

2.21 × 10²⁴ atoms Al

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

1. Set up:
   `\displaystyle 2.21 \cdot 10^(24) \ atoms \ Al((1 \ mol \ Al)/(6.022 \cdot 10^(23) \ atoms \ Al))`
2. Divide:
   `\displaystyle 3.66988 \ mol \ Al`

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.66988 mol Al ≈ 3.67 mol Al