Question

A dog running at 7.92 m/s slows down to 3.22 m/s in 4.88 s. How far does he go during this period of time?

Answer 1

the distance traveled by the dog is 27.18 m.

Step-by-step explanation:

Given;

initial velocity of the dog, u = 7.92 m/s

final velocity of the dog, v = 3.22 m/s

time of motion, t = 4.88 s

The distance traveled by the dog is calculated as;

`s = ((v+u)/(2) )t\\\\s = ((7.92 + 3.22)/(2) )(4.88)\\\\s = 27.18 \ m`

Therefore, the distance traveled by the dog is 27.18 m.