Question

Which shows the correct substitution of the values a, b, and c from the equation 1 = –2x + 3x2 + 1 into the quadratic formula? Quadratic formula:

Answer 1

`1=-2x+3x^2+1\\\\3x^2-2x+1-1=0\\\\3x^2-2x=0\\\\\boxed{a=3;\ b=-2;\ c=0}`

Answer 2

`a=3`,
`b=-2` and
`c=0`.

Explanation:

We have been given an equation
`1=-2x+3x^2+1`.

We know that a quadratic equation is in form
`ax^2+bx+c`.

First of all, we need to convert our given equation in standard quadratic equation as shown:

`1-1=-2x+3x^2+1-1`

`0=-2x+3x^2`

`-2x+3x^2=0`

`3x^2-2x=0`

Upon comparing our equation with standard quadratic equation we can see that
`a=3`,
`b=-2` and
`c=0`.