Question

Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?

Answer 1

it is in form
0=ax^2+bx+c
0=-3x^2-2x+6
a=-3
b=-2
c=6

so
x=
`(-b+/- √(b^2-4ac) )/(2a)`
x=
`(-(-2)+/- √((-2)^2-4(-3)(6)) )/(2(-3))`
x=
`(2+/- √(4+72) )/(-6)`
x=
`(2+/- √(76) )/(-6)`
x=
`(2+/- 2√(19) )/(-6)`
x=
`(1+/- √(19) )/(-3)`
x=
`(1+ √(19) )/(-3)` or
`(1- √(19) )/(-3)`