Question

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.

Answer 1

Molar mass H2SO4 = 98 g/mol

number of moles:

73,5 / 98 => 0.75 moles

Volume = 3.0 L

M = n / V

M = 0.75 / 3.0

M = 0.25 mol/L

hope this helps!

Answer 2

Answer: 0.25M

Step-by-step explanation:

Molarity : It is defined as the number of moles of solute present in one liter of solution.

`Molarity=\frac{\text{given mass of compound}}{\text{molar mass of compound}* \text{volume of solution is L}}`

Given mass of
`H_2SO_4` = 73.5 g

Molar mass of
`H_2SO_4` = 98g/mol

Volume of solution = 3.0L

`Molarity=(73.5g)/(98g/mol* 3L)=0.25M`