Question

Factor completely. 49t 6 - 4k 8

Answer 1

(7t³ - 2k4)(7t³ - 2k4) is the correct awnser

Answer 2

Answer: It will become,

`49t^6-4k^4=(7t^3-2k^4)(7t^3+2k^4)`

Explanation:

Since we have given that

`49t^6-4k^8`

We need to factorise the above expression:

`49t^6-4k^8\\\\=(7^2(t^2)^3-2^2(k^2)^4\\\\=(7t^3)^2-(2k^4)^2`

So, we can apply the identity :

`a^2-b^2=(a+b)(a-b)`

Here,

`a=7t^3\\\\b=2k^4`

so, it will become,

`49t^6-4k^4=(7t^3-2k^4)(7t^3+2k^4)`