Question

The density of gold is approximately 19.2 g/cm3. What is the mass of a sample of gold that displaces 20.0 cm3 of water? Round your answer to the correct number of significant figures.

Answer 1

Density = 19.2 g/cm³

Volume = 20.0 cm³

Mass = ?

D = m / V

19.2 = m / 20.0

m = 19.2 x 20.0

m = 384.0 g

hope this helps!

Answer 2

384.0 grams is the mass of a sample of gold that displaces 20.0
`cm^3` of water.

Step-by-step explanation:

Density of gold =
`d=19.2 g/cm^3`

Volume of water displaced gold =
`20.0 cm^3`

Volume of water displaced is equal to the volume occupied by the gold sample.

Volume of the gold , v =
`20.0 cm^3`

`Density =(Mass)/(Volume)`

Mass of gold :

`Density\time Volume =19.2 g/cm^3* 20.0 cm^3= 384.0 g`

Mass of gold = 384.0 g