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If y = 1 i, then y3 − 3y2
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If y = 1 i, then y3 − 3y2
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Feb 20, 2017
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If y = 1 i, then y3 − 3y2
Mathematics
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IDisposable
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y = 1i = i
y³ - 3y²
(i)³ - 3(i)² i² = -1, i³ = i²(i) = -i
i³ - 3i²
-i - 3(-1)
-i + 3
Rickest Rick
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Feb 23, 2017
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Rickest Rick
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y^3-3y^2
(1+i)^3-3(1+i)^2
remember
(1+i)^3=(1+i)(1+i)^2
(1+i)(1+i)^2-3(1+i)^2
factor out (1+i)^2
(1+i)^2((1+i)-3)
(1+i)^2(1+i-3)
(1+i)^2(i-2)
(1+i)(1+i)(i-2)
(1+2i-1)(i-2)
(2i)(i-2)
-2-4i
Chaotic Pechan
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Feb 27, 2017
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