Question

Evaluate the function ƒ(x) = − (x2 − 1) and simplify at the indicated value: ƒ(−a) = ?

Answer 1

f(x)=-x^2+1
for -a
remember pemdas
exponenets before multiply

for -x^2, it is (x^2) first, then times -1

f(x)=-(-a)^2+1
f(x)=-(a^2)+1
f(x)=-a^2+1

Answer 2

`f(-a)=-a^2+1`

Explanation:

We have been a function
`f(x)=-(x^2-1)`. We are asked to simplify our function at the indicated value
`f(-a)`.

To find
`f(-a)` for our given function, we will substitute
`x=-a` in our given function as:

`f(-a)=-((-a)^2-1)`

We know that a negative number raised to an even power results in positive, so our function would be:

`f(-a)=-(a^2-1)`

Using distributive property
`a(b+c)=ab+ac`, we will get:

`f(-a)=-1*a^2-1*-1`

`f(-a)=-a^2+1`

Therefore, the value of
`f(-a)` is
`-a^2+1`.