Question

Oxidation and reduction half-reactions.... . A) 2H2 + O2 =>2H2O. Oxidation half-reaction:. Reduction half-reaction:. . B) MnO2(s) + 4HCl(aq) => MnCl2(aq) + Cl2(g) + 2H2O(l). Oxidation half-reaction:. Reduction half-reaction. . 3) S(s)+ 6HNO3(aq) => SO3(g)+ 3H2O(l) + 6NO2(g). Oxidation half-reaction:. Reduction half reaction:. . *Best response and I will become a fan to whoever helps me with this.*. Thanks :)

Answer 1

1N 2O 3R

Step-by-step explanation:

Answer 2

In a redox reaction, the half reduction which reduction occurs involves the element which has a charge that decreases after the reaction. The oxidation reaction involves an element with an increased charge after the reaction. We use H+ to balance H and H2O to balance O.
1) oxidation: 2H2 + 2H2O -> 2H2O + 4H+ + 4e- reduction: O2 + 4H+ + 4e- -> 2H2O
2) oxidation: 2Cl- --> Cl2 + 2e- reduction: MnO2 + 4H+ + 2e- --> Mn2+ + 2H2O
3) oxidation: S(s) + 3H2O --> SO3(g) + 6H+ + 6e- reduction: 6NO3^- + 6H+ + 6e- --> 6NO2 + 6H2O