Potential roots of q(x) = 6x3 19x2 – 15x

asked Aug 19, 2017 212k views

4 votes

Potential roots of q(x) = 6x3 19x2 – 15x – 28

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6 votes

Hello,

q(x)=6x^3+19x²-15x-28

28/6=14/3
Potentiel roots are +/-1/3, +/- 2/3,+/-7/3, +/- 14/3

Kudit answered Aug 21, 2017

by Kudit

8.0k points

1 vote

Answer:

2/3, 7/2, 14 for edge

Brandon Barney answered Aug 23, 2017