Question

Find the sum of the first 50 terms of the sequence below an=3n+2

Answer 1

Answer: it is 3925 the verified answer is wrong

Answer 2

We have the next given sequence:

`a_n=3n+2`

Now, we need to sum up the first 50 terms:

`\sum_{n\mathop{=}1}^(50)3n+2`

Then, we replace n and then add up the results:

(3(1)+2) +(3(2)+2) + (3(3)+2) + (3(4)+2)................(3(50)+2)

=

5 + 8 + 11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 + 35 + 38 + 41 + 44 + 47 + 50 + 53 + 56 + 59 + 62 + 65 + 68 + 71 + 74 + 77 + 80 + 83 + 86 + 89 + 92 + 95 + 98 + 101 + 104 + 107 + 110 + 113 + 116 .

+ 119 + 122 + 125 + 128 + 131 + 134 + 137 + 140 + 143 + 146 + 149 + 152

The sum is equal to 3925.

The answer is 3825.