Answer:
Explanation:
1) Solve the equation: [4ax - (a + b)](a + b) = 0, where a and b are constants.
- if a + b = 0, then x has infinitely many solutions
or
- 4ax = a + b
- x = (a + b)/4a, a≠0
2) Solve the equation m²x + 1 = m(x + 1), where m is a parameter.
- m²x + 1 - mx - m = 0
- (m²- m)x = m - 1
- m(m - 1)x = m - 1
- mx = 1
- x = 1/m, m≠0
3) Given that the equation a(2x - 1) = 3x - 3 has no solution, find the value of the parameter a.
- a(2x - 1) = 3x - 3
- 2ax - a = 3x - 3
- 2ax - 3x = a - 3
- (2a - 3)x = a - 3
- x = (a - 3)/(2a - 3)
The equation has no solution if: