Question

A 3.0 L solution contains 73.5 g of H2SO4. Calculate the molar concentration of the solution.

Answer 1

Molar mass :


`H_2SO_4= 1*2+32+16*4= 98g/mol`

Number of moles:


`n = (solute)/(molar( mass))`


`n = (73.5g)/(98g/mol)`


`n=0.75 (moles)`

Volume = 3.0 L


`M = (n)/(V)`


`M = (0.75(moles))/(3.0L)`


`M = 0.25 mol/L ^(-1)`

hope this helps!