Question

2a squared+3a+1 How do I factor the trinomial of this equation?

Answer 1

`2a^2+3a+1\\\\x=2;\ y=3;\ z=1\\\\\Delta=y^2-4xz\\if\ \Delta \ \textgreater \ 0\ then\ a_1=(-y-\sqrt\Delta)/(2x)\ and\ a_2=(-y+\sqrt\Delta)/(2x)\\\\\Delta=3^2-4\cdot2\cdot1=9-8=1 \ \textgreater \ 0\\\sqrt\Delta=\sqrt1=1\\\\a_1=(-3-1)/(2\cdot2)=(-4)/(4)=-1;\ a_2=(-3+1)/(2\cdot2)=(-2)/(4)=-(1)/(2)\\\\2a^2+3a+1=2(a+1)\left(a+(1)/(2)\right)=(a+1)(2a+1)\\\\other\ method\\\\2a^2+3a+1=2a^2+2a+a+1=2a(a+1)+1(a+1)\\=(a+1)(2a+1)`