Question

If f(x) = 1 – x, which value is equivalent to |f(i)|?

Answer 1

f(x) = 1 – x

f(i) = 1 - i

|f(i)| = √(1² + (-1)²) = √(1 + 1) = √2

Answer 2

If f(x) = 1 – x then, value of |f(i)| is:

√2

Explanation:

f(x) = 1 – x

Then, f(i) = 1 - i

We know that if f(z)=x+iy then, |f(z)|=
`√(x^2+y^2)`

Hence, |f(i)| =
`√(1^2+(-1)^2)`

=
`√(1+1)`

= √2

Hence, if f(x) = 1 – x then, value of |f(i)| is:

√2