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1 vote
Find the product. (do not use spaces in your answer.)

d ^j · d ^k

User Miorey
by
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2 Answers

2 votes

d^j\cdot d^k=d^(j+k)
User Shamell
by
8.7k points
4 votes

Answer: The product would be
d^(j+k)

Explanation:

Since we have given that


d^j.d^k

We need to find the product.

As we know that


a^m* a^n=a^(m+n)

So, we will use the above exponential law and it becomes,


d^j.d^k=d^(j+k)

Hence, the product would be
d^(j+k)

User ViviG
by
9.0k points

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